-4=x^2+8x+12

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Solution for -4=x^2+8x+12 equation: 



-4=x^2+8x+12

We move all terms to the left:

-4-(x^2+8x+12)=0

We get rid of parentheses

-x^2-8x-12-4=0

We add all the numbers together, and all the variables

-1x^2-8x-16=0

a = -1; b = -8; c = -16;
Δ = b2-4ac
Δ = -82-4·(-1)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{-2}=-4$

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